3x^2(2x+1)=27(2x+1)

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Solution for 3x^2(2x+1)=27(2x+1) equation: 



3x^2(2x+1)=27(2x+1)

We move all terms to the left:

3x^2(2x+1)-(27(2x+1))=0



We calculate terms in parentheses: -(27(2x+1)), so:

27(2x+1)

We multiply parentheses

54x+27

Back to the equation:

-(54x+27)



We get rid of parentheses

3x^2(2x+1)-54x-27=0

We move all terms containing x to the left, all other terms to the right

3x^2(2x+1)-54x=27

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